Vở bài tập Toán lớp 3 Tập 2 trang 32, 33 Bài 53 Tiết 1 | Kết nối tri thức
Have you been looking for effective and detailed solutions for your 3rd grade math homework from Exercise Book 2, specifically on Pages 32-33, Lesson 1? Look no further! At Kienthucykhoa.com, we provide top-notch assistance to help students easily complete their math exercises at home.
Solving Math Homework: Exercise Book 2, Pages 32-33, Lesson 1 – Kienthucykhoa.com
Exercise 1: Filling in the Blanks
In the first exercise on Page 32, you are required to write the appropriate numbers in the given blanks according to the pattern. Here’s how you can do it:
Side length of a square:
- 15 cm
- 9 cm
- …(missing value)… cm
- 10 dm
Perimeter of the square:
- 60 cm
- …(missing value)… cm
- 36 cm
- …(missing value)… dm
Solution:
The formula for calculating the perimeter of a square is: Perimeter = (Length of one side) × 4
To find the length of one side of the square, we can use the formula: Length of one side = Perimeter of the square ÷ 4
Let’s fill in the missing values:
Side length of a square:
- 15 cm
- 9 cm
- 9 cm
- 10 dm
Perimeter of the square:
- 60 cm
- 36 cm
- 36 cm
- 40 dm
Exercise 2: Calculating the Perimeter of a Rectangle
In Exercise 2 on Page 32, you need to calculate the perimeter of a rectangle with given length and width. Here are the two parts of this exercise:
a) Calculate the perimeter of a rectangle with a length of 3 dm and a width of 5 cm.
b) Calculate the perimeter of a rectangle with a length of 3 dm and a width of 20 cm.
Solution:
a) First, let’s convert 3 dm to cm: 3 dm = 30 cm
The formula for calculating the perimeter of a rectangle is: Perimeter = (Length + Width) × 2
For the given values, the perimeter of the rectangle is: (30 + 5) × 2 = 70 cm
Answer: 70 cm
b) Again, let’s convert 3 dm to cm: 3 dm = 30 cm
The perimeter of the rectangle is: (30 + 20) × 2 = 120 cm
Answer: 120 cm
Exercise 3: Perimeter of a Composite Square
In Exercise 3 on Page 32, you are asked to calculate the perimeter of a square made up of four smaller squares. Each side of the smaller squares is 50 cm. Here’s how you can do it:
Solution:
The length of a square used to cover the entire area is obtained by multiplying the side length of each smaller square by 4. So, the length of the composite square is: 50 × 4 = 200 cm
The perimeter of the composite square is simply 4 times the length of one side: 200 × 4 = 800 cm
Answer: 800 cm
Exercise 4: Fencing the Flower Gardens
In Exercise 4 on Page 33, Ms. Hoa is fencing different pieces of land to plant roses, daisies, and orchids. It is known that the adjacent pieces of land are 1m apart (as shown in the diagram).
a) Let’s fill in the blanks:
Piece of land A has a fence that is …m long, piece of land B has a fence that is …m long, and piece of land C has a fence that is …m long.
b) Circle the correct letter:
Which piece of land is dedicated to growing orchids?
A. Piece of land A
B. Piece of land B
C. Piece of land C
Solution:
Let’s calculate the lengths of the fences for each piece of land:
+) Garden A:
- Length of the fence = 1 × 4 = 4 m
- Width of the fence = 1 × 3 = 3 m
- Perimeter of the fence = (4 + 3) × 2 = 14 m
+) Garden B:
- Length of the fence = 1 × 5 = 5 m
- Width of the fence = 1 × 4 = 4 m
- Perimeter of the fence = (4 + 5) × 2 = 18 m
+) Garden C:
- Length of one side of the fence = 1 × 4 = 4 m
- Perimeter of the fence = 4 × 4 = 16 m
a) Based on the calculations, the lengths of the fences are:
- Piece of land A: 4 m
- Piece of land B: 5 m
- Piece of land C: 4 m
b) The piece of land dedicated to growing orchids is Piece of land C.
Circle “C”.
For more detailed and helpful solutions for Exercise Book 2, Pages 34-35, Lesson 2 and Lesson 3, check out the following links: